Group+8

=__Title:__ The Effect of Concentration on the Reaction Between Potassium Iodide and Lead Nitrate=

**+ __Question:__** How does the concentration of Potassium Iodide and Lead Nitrate affect the mass of Lead Iodide formed after the reaction has taken place?


 * __Hypothesis:__** As the concentration of the reactants increases, the mass of the solid product formed will increase for the more concentrated the solution is, the more particles of the reactants there will be, this means that there will be more collision of the reactants when they react with each other and the more collision means the higher the mass of the product formed will be.


 * __Variables__**
 * **Independent Variables:** The concentration of Potassium Iodide and Lead Nitrate.
 * **Dependent Variables:** Mass of Lead Iodide.
 * **Controlled Variables:** Size of Beakers, Mass of Filter Paper, The volume of Potassium Iodide and Lead Nitrate.


 * __Materials:__**[[image:382N900.jpg width="129" height="158" align="right" caption=" " link="http://www.escience.ca/GFX/PRODS/382N900.jpg"]][[image:Graduated-cylinder.gif width="45" height="156" align="right" caption="    " link="http://www.escience.ca/GFX/PRODS/382N900.jpg"]]
 * Three pieces of Filter Paper
 * Three 250mL Erlenmeyer Flasks
 * Three 150mL Beakers
 * 24mL of Potassium Iodide (10ml on the first try, 8ml on the second, and 6ml on the third)
 * 24mL of Lead Nitrate (10ml on the first mixture, 8ml on the second, and 6ml on the third)
 * 6mL of Distilled Water (0ml on the first mixture, 2ml on the second, and 4ml on the third)
 * Two 25mL graduated cylinder
 * Electric Balance Beam
 * Three Funnels
 * Squeezy distilled water bottle

__**Method:**__
 * 1) Prepare all the materials needed for the experiment.
 * 2) Pour 10ml of both Potassium Iodide and Lead Nitrate into separate 25mL graduated cylinders.
 * 3) Wait for the Potassium Iodide and Lead Nitrate to react in a 150ml beaker.
 * 4) Weigh the mass of 3 pieces of filter paper on an electric balance beam.
 * 5) Record the results.
 * 6) Fold the piece of filter paper in fourths and mould it to place so it fits and forms into the shape of a funnel. If necessary, wet the filter paper a little bit to keep the filter paper in place.
 * 7) Put one piece of filter paper on a funnel and place the funnel on one of the 250ml Erlenmeyer flasks.
 * 8) Empty the mixture of Lead Iodide on the filter paper. Be careful that the mixture sits directly in the middle of the filter paper and that it doesn't spill.
 * 9) Use the squeezy distilled water bottle to clean out the rest of the Lead Iodide mixture from the beaker. It will stick because the mixture is very sticky. Empty the mixture on the filter paper.
 * 10) It will take some time for all the liquid of the Lead Iodide mixture to soak through the filter paper, so set the Erlenmeyer Flask aside.
 * 11) Repeat steps 2-4 except this time the mixture of Lead Iodide will have the concentration of 0.8M (to make concentration of 0.8M, place 8ml of both Potassium Iodide and Lead Nitrate into separate graduated cylinders, then place 2ml of water in each graduated cylinder).
 * 12) Repeat steps 2-4 once again this time with the mixture of Lead Iodide will have a concentration of 0.6M (to make concentration of 0.6M, place 6ml of both Potassium Iodide and Lead Nitrate into separate graduated cylinders, then place 4ml of water in each graduated cylinder).
 * 13) Leave the Lead Iodide mixtures to dry on separate Erlenmeyer flasks.
 * 14) Once the Lead Iodide is dry, mass the mixtures with the filter paper.
 * 15) Subtract the filter paper mass from the mass of Lead Iodide with the filter paper.

__**Data Collection:

1M**__

Mass of Filter Paper: 1.254g Mass of Filter Paper and Lead Iodide:3.2227g Mass of Lead Iodide: 3.2227-1.254= 1.9687g

__**0.8M**__

Mass of Filter Paper: 1.228g Mass of Filter Paper and Lead Iodide: 2.6703g Mass of Lead Iodide: 2.6703-1.228= 1.4423g

__**0.6M**__

Mass of Filter Paper: 1.2441g Mass of Filter Paper and Lead Iodide: 2.3880g Mass of Lead Iodide: 2.3880-1.2441= 1.1439g


 * __Data Processing:__





__Conclusion:__** Our question on the relationship between concentration Potassium Iodide, Lead Nitrate and the mass of the Lead Iodide. Our hypothesis was correct. The higher the concentration of the Potassium Iodide and Lead Nitrate, the greater the mass of the Lead Iodide. The experiment with the greatest mass was with our greatest concentration, which was 1M. When we decreased the amount of Potassium Iodide and raised the amount of water in the mixture, the mass of Lead Iodide decreased. The graph shows the positive relationship between our dependent and independent variables.


 * __Evaluation:__** On our first try, we did not manage to have clear liquid in the flasks because we accidentally poured the mixture not only on the filter paper but also on the side of it. The liquid went through the side of the filter paper instead of the middle, so not all of the liquid was filtered. Some of the Lead Iodide got stuck to the glass beaker (because of it's stickiness) which decreased the mass, so the results aren't that accurate. To improve our experiment we would need something that thoroughly cleans the filter paper from all the Lead Iodide formed, because we got a lot of it also stuck on the filter paper. This could have affected our experiment. A question we have in mind after doing this experiment is, would the concentration of Potassium Iodide and Lead Nitrate affect the color of Lead Iodide?